Polydisperse oil aerosol is used to challenge the “integrity” and measure the leakage of filter media, the filter assembly, framework, and connections, etc. Therefore, a common question asked is:
Question: “How much aerosol is needed to test a typical filter?”
Answer: Approximately eleven (11) drops for a 24 in. x 24 in. x 12 in. filter operating at 1,000 cfm.
Example: An example below uses 10 ug/l (micrograms per liter) of PAO-4 as an upstream challenge.
Assuming a typical 24 in. x 24 in. x 12 in. HEPA filter has an average of 65 pleats and the pleat size is 22.5 in. x 10.5 in., which equates to approximately 213 ft2 of media.
To determine the amount of liquid introduced to the filter, the necessary scan time of the filter must be calculated. Using a photometer with industry standard rectangular-shaped probe:
- Assuming a scan rate at 2 in./sec, as specified by most filter leak scan testing standards, 12 seconds is necessary to span one 24 in. pass. A 24 in. x 24 in. cross section requires eight (8) passes, with overlapping strokes, and, thus, a total time of 96 seconds or 1.6 minutes.
The quantity of oil (liquid) necessary to generate a 10 ug/l upstream challenge aerosol for a 1000 cfm filter is calculated by:
- 1,000 cfm x 28.3 (cfm to lpm conversion) x 10 ug/l x 0.00001 (g/ug) = 0.283 g/min of liquid. Therefore, 1.6 min x 0.283 g / 0.819 g/ml (density of PAO-4) = 0.55 ml PAO-4.
For low viscosity liquids, it is generally considered appropriate to allow 20 drops per 1 ml of liquid. This would equate to eleven (11) drops of PAO-4 necessary to challenge a 24 in. x 24 in. x 12 in. 1000 cfm filter using a 10 ug/l challenge. For a point of reference, this is comparable to eleven (11) drops of liquid spread over a surface area approximately equal to that of the “inside paint” (i.e., 3 second area) of a basketball court.
Comments
0 comments
Please sign in to leave a comment.